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๋ชฉ๋กํ๋ก๊ทธ๋๋จธ์ค (2)
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์ฝ๋ ์ฒ๋ฆฌํ๊ธฐ description: https://school.programmers.co.kr/learn/courses/30/lessons/181932 My answer was function solution(code) { let answer = ''; let mode = 0; for(let idx = 0; idx < code.length; idx++) { const firstCondition = !mode && (idx % 2 === 0) const secondCondition = mode && (idx % 2 === 1) if(code[idx] !== '1' && (firstCondition || secondCondition)) answer += code[idx]; mode = code[idx] =..
๋ฌธ์์ด ์๊ธฐ Description ๊ธธ์ด๊ฐ ๊ฐ์ ๋ ๋ฌธ์์ด str1๊ณผ str2๊ฐ ์ฃผ์ด์ง๋๋ค. ๋ ๋ฌธ์์ด์ ๊ฐ ๋ฌธ์๊ฐ ์์์๋ถํฐ ์๋ก ๋ฒ๊ฐ์๊ฐ๋ฉด์ ํ ๋ฒ์ฉ ๋ฑ์ฅํ๋ ๋ฌธ์์ด์ ๋ง๋ค์ด return ํ๋ solution ํจ์๋ฅผ ์์ฑํด ์ฃผ์ธ์. ์ ์ถ๋ ฅ ์ str1. str2. result "aaaaa" "bbbbb" "ababababab" My answer was function solution(str1, str2) { var answer = ''; for(let i = 0; i < str1.length; i++) { answer += str1[i] + str2[i] } return answer; } Best answer was function solution(str1, str2) { return [...str1]..